document.write( "Question 490508: please solve this one...
\n" ); document.write( "A man divides $10,000 in two investments, one at 10% and the other at 30%. Find how much is invested at each rate so that the two investments produce the same income annually.. the answer is $2,500 and $7,500.. I just need the solution thank you.. \n" ); document.write( "
Algebra.Com's Answer #334123 by mananth(16949)\"\" \"About 
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Investment I 10.00% per annum ---x
\n" ); document.write( "Investment II 30.00% per annum ---y
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\n" ); document.write( "x + y= 10000 ------------------------1
\n" ); document.write( "10.00% x + 30.00% y = $860.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "10 x -30 y = 0 --------2
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\n" ); document.write( "Multiply (1) by -10
\n" ); document.write( "we get
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\n" ); document.write( "-10 x -10 y = -100000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x -40 y = -100000
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\n" ); document.write( "divide by -40
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\n" ); document.write( "y = 2500 investment at 30.00%
\n" ); document.write( "Balance 7500 investment at 10.00%
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