document.write( "Question 489406: 1 minus radical3 all divided by 3radical2 minus radical6.\r
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\n" ); document.write( "\n" ); document.write( "I am trying to rationalize the denominator and am totally lost. Will somebody please send me step by step directions and a final answer please? Thank you! \n" ); document.write( "
Algebra.Com's Answer #334122 by lwsshak3(11628)\"\" \"About 
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1 minus radical3 all divided by 3radical2 minus radical6
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\n" ); document.write( "(1-√3)/(3√2-√6)
\n" ); document.write( "multiply top and bottom by (3√2+√6)
\n" ); document.write( "(1-√3) (3√2+√6)/(3√2-√6) (3√2+√6)
\n" ); document.write( "calculating numerator and denominator separately
\n" ); document.write( "numerator:
\n" ); document.write( "FOIL
\n" ); document.write( "(1-√3) (3√2+√6)=3√2+√6-3√6-√18
\n" ); document.write( "=3√2-2√6-3√2=-2√6
\n" ); document.write( "..
\n" ); document.write( "Denominator:
\n" ); document.write( "(3√2-√6) (3√2+√6)
\n" ); document.write( "Difference of squares
\n" ); document.write( "18-6=12
\n" ); document.write( "..
\n" ); document.write( "(1-√3)/(3√2-√6)=-2√6/12=-√6/2 \n" ); document.write( "
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