document.write( "Question 147422: Buddy invested 15000. He put some money in at 4% and remainder in at 5%. At the end of the year he had $690 in interest. How much did he invest at 4% and how much did he invest at 5%? \n" ); document.write( "
Algebra.Com's Answer #334120 by ej_03(8)\"\" \"About 
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let x=4%
\n" ); document.write( " y=5%\r
\n" ); document.write( "\n" ); document.write( "eq1 x+y=15000
\n" ); document.write( " y=15000=x
\n" ); document.write( "eq2 .04x+.05(15000-x)=690\r
\n" ); document.write( "\n" ); document.write( "perform the indicated operations in the equation:
\n" ); document.write( ".04x+.05(15000-x)=690
\n" ); document.write( ".04x+750-.05x=690
\n" ); document.write( ".04x-.05x=690-750
\n" ); document.write( ".01x/.01=60/.01
\n" ); document.write( "x=6000\r
\n" ); document.write( "\n" ); document.write( "y=15000-6000=9000
\n" ); document.write( "therefore buddy invested 6000 at 4% and 9000 at 5%.
\n" ); document.write( "hope this other solution help you through...=)
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