document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487661>Question 487661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Just wondering if someone could explain how to solve to find x: \r<BR>\n" );
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document.write( "2 × (0.1)^x+1 = 25\r<BR>\n" );
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document.write( "thanking you<BR>\n" );
document.write( "Tracey </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334117 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ust wondering if someone could explain how to solve to find x: <BR>\n" );
document.write( "2 × (0.1)^x+1 = 25 <BR>\n" );
document.write( "**<BR>\n" );
document.write( "2 × (0.1)^x+1 = 25<BR>\n" );
document.write( "2*(0.1)^x=25-1=24<BR>\n" );
document.write( "(0.1)^x=24/2=12<BR>\n" );
document.write( "take log of both sides<BR>\n" );
document.write( "xlog(0.1)=log12<BR>\n" );
document.write( "x=log12/log(0.1)<BR>\n" );
document.write( "x=1.0792/-1<BR>\n" );
document.write( "x=-1.0792 </SPAN>\n" );
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