document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490498>Question 490498</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is one unit more than it's width. if the area is 30 square units, find the demnsions of the rectangle. translate the problem into an equation.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334112 by </B><A HREF=/tutors/aboutme.mpl?userid=supriyo_bol><B>supriyo_bol(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=supriyo_bol><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be = L unit<BR>\n" );
document.write( "Length = (L+1) unit<BR>\n" );
document.write( "Area= L(L+1)<BR>\n" );
document.write( "Therefore <BR>\n" );
document.write( "L(L+1)=30<BR>\n" );
document.write( "L2+L-30=0 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );