document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50252>Question 50252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have to use the substitution method.\r<BR>\n" );
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document.write( "3x+4y=14<BR>\n" );
document.write( "y=-5/2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33410 by </B><A HREF=/tutors/aboutme.mpl?userid=hulamc723><B>hulamc723(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hulamc723><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+4y=14<BR>\n" );
document.write( "y=-5/2x\r<BR>\n" );
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document.write( "Actually, you will be quite baffled to know all you need to do is stick -5/2x in for y in the top equation!<BR>\n" );
document.write( " Right now i dont have time to solve but just substitute that ok, sorry for this!!!!<BR>\n" );
document.write( "-mc </SPAN>\n" );
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