document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490458>Question 490458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how the basic form quadratic equation ax^2+bx+c=0 solves for x to become the quadratic formula: (-b+/-square root (b^2-4ac))/2a? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334090 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> done by completing the square\r<BR>\n" );
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document.write( "subtracting c ___ ax^2 + bx = -c\r<BR>\n" );
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document.write( "dividing by a ___ x^2 + (b/a)x = -c/a\r<BR>\n" );
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document.write( "adding half of the x-term coefficient, squared ___ x^2 + (b/a)x + (b/2a)^2 = (-c/a) + (b/2a)^2\r<BR>\n" );
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document.write( "x^2 + (b/a)x + (b/2a)^2 = (-c/a) + [(b^2)/(4a^2)] ___ x^2 + (b/a)x + (b/2a)^2 = [(-4ac)/(4a^2)] + [(b^2)/(4a^2)]\r<BR>\n" );
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document.write( "combining terms and taking sqrt ___ x + (b/2a) = ± [sqrt(b^2 - 4ac)] / 2a\r<BR>\n" );
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document.write( "subtracting (b/2a) and combining terms ___ x = {-b ± [sqrt(b^2 - 4ac)]} / 2a </SPAN>\n" );
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