document.write( "Question 490005: The equation of a circle where A and B are the endpoints of the diameter
\n" ); document.write( "Using the points A(4,−9 ) and B(−12,−3 )
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Algebra.Com's Answer #334067 by lwsshak3(11628)\"\" \"About 
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The equation of a circle where A and B are the endpoints of the diameter
\n" ); document.write( "Using the points A(4,−9 ) and B(−12,−3 )
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\n" ); document.write( "Standard form of an equation for a circle: (x-h)^2+(y-k)^=r^2, (h,k) being (x,y) coordinates of the center and r=radius
\n" ); document.write( "..
\n" ); document.write( "Using distance formula to find diameter of circle:
\n" ); document.write( "d=√[(x1-x2)^2+(y1-y2)^2]
\n" ); document.write( "d=√[(-12-4)^2+(-3-(-9))^2]
\n" ); document.write( "d=√[(-16)^2+(6)^2]
\n" ); document.write( "d=√(256+36)=√292
\n" ); document.write( "r=d/2=√292/2
\n" ); document.write( "r^2=292/4=73
\n" ); document.write( "..
\n" ); document.write( "Using midpoint formula to find coordinates of the center:
\n" ); document.write( "(x1+x2)/2,(y1+y2/2=(-12+4)/2,(-3+(-9))/2=(-4,-6)
\n" ); document.write( "..
\n" ); document.write( "Equation:
\n" ); document.write( "(x+4)^2+(y+6)^2=73
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