document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489511>Question 489511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given m<ABC= 94 degrees; find m<CBD.... angle ABD has (3x-15)in the middle of the angle and CBD has (x-7) in the middle of the angle.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #334041 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=334041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Angle ABC and angle CBD = angle ABD.<BR>\n" );
document.write( "94 + x - 7 = 3x - 15<BR>\n" );
document.write( "87 + x = 3x - 15<BR>\n" );
document.write( "102 = 2x<BR>\n" );
document.write( "51 = x<BR>\n" );
document.write( "ABD = 3(51) - 15 = 138 degrees<BR>\n" );
document.write( "CBD = 51 - 7 = 44 degrees (This is what we had been ask for.)<BR>\n" );
document.write( "44 degrees + 94 degrees = 138 degrees.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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