document.write( "Question 489785: I need help in finding the coordinates of the vertex for the parabola defined by the given quadratic function f(x) = -x^2 -4x + 8 \n" ); document.write( "
Algebra.Com's Answer #334038 by MathTherapy(10552)\"\" \"About 
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I need help in finding the coordinates of the vertex for the parabola defined by the given quadratic function f(x) = -x^2 -4x + 8 \r
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\n" ); document.write( "\n" ); document.write( "To find the axis of symmetry, or the x-coordinate of the vertex, we use the formula, \"-+b%2F2a\", where a = - 1, and b = - 4\r
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\n" ); document.write( "\n" ); document.write( "That results in: x = \"-%28%28-4%29%2F%282%2A-1%29%29\" = \"-%28-4%29%2F-2\" = - 2\r
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\n" ); document.write( "\n" ); document.write( "Now, substituting - 2 for x in the equation, we get: f(x) or y = \"-%28-+2%29%5E2+-+4%28-+2%29+%2B+8\" ------ f(x) or y = - 4 + 8 + 8 ----- y = 12\r
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\n" ); document.write( "\n" ); document.write( "Since the x and y-coordinates are - 2, and 12, respectively, then the coordinates of the vertex of the parabola are (\"highlight_green%28-+2%29\", \"highlight_green%2812%29\")\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to MathMadEzy@aol.com
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