document.write( "Question 490332: Please help...am so confused...taking stats online and have no teacher...thanks a bunch\r
\n" );
document.write( "\n" );
document.write( "The diameters of grapefruits in a certain orchard are normally distributed with a mean of 5.44 inches and a standard deviation of 0.41 inches. Show all work. \r
\n" );
document.write( "\n" );
document.write( "(A) What percentage of the grapefruits in this orchard is larger than 5.36 inches? \r
\n" );
document.write( "\n" );
document.write( "(B) A random sample of 100 grapefruits is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 5.36 inches?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #333998 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The diameters of grapefruits in a certain orchard are normally distributed with a mean of 5.44 inches and a standard deviation of 0.41 inches. Show all work. \n" ); document.write( "(A) What percentage of the grapefruits in this orchard is larger than 5.36 inches? \n" ); document.write( "--- \n" ); document.write( "z(5.36) = (5.36-5.44)/0.41 = -0.1951 \n" ); document.write( "P(x > 5.36) = P(z > -0.1951) = 0.5774 \n" ); document.write( "=============================================== \n" ); document.write( "(B) A random sample of 100 grapefruits is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 5.36 inches? \n" ); document.write( "t(5.36) = (5.36-5.44)/[0.41/sqrt(100)] = -1.9512 \n" ); document.write( "--- \n" ); document.write( "P(x-bar > 5.36) = P(t > -1.9512 when df = 99) = 0.9731 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |