document.write( "Question 490332: Please help...am so confused...taking stats online and have no teacher...thanks a bunch\r
\n" ); document.write( "\n" ); document.write( "The diameters of grapefruits in a certain orchard are normally distributed with a mean of 5.44 inches and a standard deviation of 0.41 inches. Show all work. \r
\n" ); document.write( "\n" ); document.write( "(A) What percentage of the grapefruits in this orchard is larger than 5.36 inches? \r
\n" ); document.write( "\n" ); document.write( "(B) A random sample of 100 grapefruits is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 5.36 inches?
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Algebra.Com's Answer #333998 by stanbon(75887)\"\" \"About 
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The diameters of grapefruits in a certain orchard are normally distributed with a mean of 5.44 inches and a standard deviation of 0.41 inches. Show all work.
\n" ); document.write( "(A) What percentage of the grapefruits in this orchard is larger than 5.36 inches?
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\n" ); document.write( "z(5.36) = (5.36-5.44)/0.41 = -0.1951
\n" ); document.write( "P(x > 5.36) = P(z > -0.1951) = 0.5774
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\n" ); document.write( "(B) A random sample of 100 grapefruits is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 5.36 inches?
\n" ); document.write( "t(5.36) = (5.36-5.44)/[0.41/sqrt(100)] = -1.9512
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\n" ); document.write( "P(x-bar > 5.36) = P(t > -1.9512 when df = 99) = 0.9731
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
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