document.write( "Question 490292: A vending machine contains nickels & dimes = $14.50
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document.write( "There are 95 more nickels than dimes.
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document.write( "Would the equation be:
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document.write( "(x+4.75) + y = $14.50\r
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document.write( "But everyway I try to figure it it comes out wrong.\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #333965 by Alan3354(69443) You can put this solution on YOUR website! A vending machine contains nickels & dimes = $14.50 \n" ); document.write( "There are 95 more nickels than dimes. \n" ); document.write( "---------------------- \n" ); document.write( "Make it 2 equations. \n" ); document.write( "n = # of nickels, d = # of dimes \n" ); document.write( "------------ \n" ); document.write( "n = d + 95 \n" ); document.write( "5n + 10d = 1450 \n" ); document.write( "5(d + 95) + 10d = 1450 \n" ); document.write( "15d + 475 = 1450 \n" ); document.write( "15d = 975 \n" ); document.write( "d = 65 dimes \n" ); document.write( "n = 160 nickels \n" ); document.write( "-------------- \n" ); document.write( "Here's another approach: \n" ); document.write( "If it's zero dimes and 95 nickels --> 475 \n" ); document.write( "Each additional nickel adds another dime, so 15 cents is added for each additional dime. \n" ); document.write( "1450 - 475 = 975 \n" ); document.write( "975/15 = 65 nickels added \n" ); document.write( "95 + 65 = 160 nickels, etc \n" ); document.write( " \n" ); document.write( " |