document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490204>Question 490204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of the diagonal in a rectangle with a length of 8 cm and a width of 6 cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333923 by </B><A HREF=/tutors/aboutme.mpl?userid=shivang+jindal><B>shivang jindal(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shivang+jindal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the quardilateral be abcd\r<BR>\n" );
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document.write( "let length be x = cd <BR>\n" );
document.write( "let breadth be y = ab\r<BR>\n" );
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document.write( "then make a diagonal\r<BR>\n" );
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document.write( "no line cd and ab will make a right angle traingle<BR>\n" );
document.write( "an bye the hypotenuse square = perpendicular square + base square\r<BR>\n" );
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document.write( "now diagonal^2 = x^2 * y^2<BR>\n" );
document.write( "so \r<BR>\n" );
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document.write( "diagonal = sqrt(x^2 + y^2) by putting values of x an y<BR>\n" );
document.write( "diagonal = sqrt(64 + 36)<BR>\n" );
document.write( "diagonal = sqrt(100)<BR>\n" );
document.write( "diagonal = 10 ans </SPAN>\n" );
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