document.write( "Question 490150: Suppose a gas tank for a car holds 12 gallons, and that the car uses 1/20 of a gallon per mile. Let X be the number of miles the car has gone since the tank was last filled.\r
\n" ); document.write( "\n" ); document.write( "A) Write an expression for the number of gallons left after \"X\" miles\r
\n" ); document.write( "\n" ); document.write( "B) How many gallons are left after 100 miles\r
\n" ); document.write( "\n" ); document.write( "C) Write an equation stating that 5 gallons are left , then solve it to find out how far the car has gone when 5 gallons remain.\r
\n" ); document.write( "\n" ); document.write( "D) How far has the car gone when it runs out of gas?
\n" ); document.write( "

Algebra.Com's Answer #333917 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(a)
\n" ); document.write( "\"++12+-+%281%2F20%29%2Ax+\"
\n" ); document.write( "(b)
\n" ); document.write( "\"+12+-+%281%2F20%29%2A100+=+7+\"
\n" ); document.write( "(c)
\n" ); document.write( "\"+5+=+12+-+%281%2F20%29%2Ax+\"
\n" ); document.write( "\"+100+=+240+-+x+\"
\n" ); document.write( "\"+x+=+240+-+100+\"
\n" ); document.write( "\"+x+=+140+\"
\n" ); document.write( "The car has gone 140 mi
\n" ); document.write( "(d)
\n" ); document.write( "\"+0+=+12+-+%281%2F20%29%2Ax+\"
\n" ); document.write( "\"+%281%2F20%29%2Ax+=+12+\"
\n" ); document.write( "\"+x+=+240+\"
\n" ); document.write( "The car has gone 240 mi
\n" ); document.write( "
\n" );