document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490140>Question 490140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square's side is increased by 2 yards, which corresponds to an increase in the area by 56 square yards. How many yards is the side of the initial square?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333908 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> original side length = x\r<BR>\n" );
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document.write( "new length = (x+2)\r<BR>\n" );
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document.write( "(x+2)^2= x^2+56\r<BR>\n" );
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document.write( "x^2+4x+4 =x^2+56<BR>\n" );
document.write( "4x+4 =56<BR>\n" );
document.write( "4x=52<BR>\n" );
document.write( "x=13 yards ---original length of side </SPAN>\n" );
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