document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490143>Question 490143</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25% antifreeze to get a mixture othat is 60% antifreeze<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333904 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------	quantity									<BR>\n" );
document.write( "Antifreeze I	25	----------------			90	gallons						<BR>\n" );
document.write( "Antifreeze II	70	----------------			x	gallons						<BR>\n" );
document.write( "Mixture	60	----------------	90	+	x	gallons						<BR>\n" );
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document.write( "25	*	90	+	70	x	=60(90+	x	)<BR>\n" );
document.write( "2250	+	70	x	=	5400	+	60	x				<BR>\n" );
document.write( "70	x	+	-60	x	=	5400	-2250				<BR>\n" );
document.write( "10	x	=	3150									<BR>\n" );
document.write( "/	10											<BR>\n" );
document.write( "x	=	315										<BR>\n" );
document.write( "		315	gallons		of	70	%	Antifreeze II				<BR>\n" );
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