document.write( "Question 6255: I am not certain how you get the answer for this, will you please show each step.\r
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document.write( "The Problem: ar^2 - brs + ars - br^2
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document.write( "I worked some of the problem:
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document.write( "ar^2 - brs + ars - br^2 = ar^2 + ars - brs - br^2
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document.write( " = a(r^2 + rs) -b(rs - r^2)
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document.write( " = (r^2 + rs)(rs - r^2)<-did the\"a\" and \"-b\" cancel out?.
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document.write( "This is the textbook's anwser:
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document.write( "r(r + s)(a - b) \r
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document.write( "I am not understanding, please help.
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document.write( "tsj\r
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Algebra.Com's Answer #3339 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Factor: ar^2 - brs + ars - br^2 \r \n" ); document.write( "\n" ); document.write( "First, group the terms containing r^2 together and group the terms containing rs together.\r \n" ); document.write( "\n" ); document.write( "(ar^2 - br^2) + (ars - brs) From the first group, factor the r^2 and from the second group, factor the rs.\r \n" ); document.write( "\n" ); document.write( "r^2(a - b) + rs(a - b) Now factor the (a - b) \n" ); document.write( "(a - b)(r^2 + rs) Finally, you can factor the r from the second group.\r \n" ); document.write( "\n" ); document.write( "r(a - b)(r + s) and this is exactly equivalent to: r(r + s)(a - b) \n" ); document.write( " |