document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490177>Question 490177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation due tomorrow! Thanks.\r<BR>\n" );
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document.write( "The supplement of an angle is 36 degrees less than twice the supplement of the complement of the angle. Find the measure of the supplement.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333887 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the angle be A, then its supplement is (180-A) and its complement is (90-A).<BR>\n" );
document.write( "180-A = (180-2(90-A))-36 Simplify.<BR>\n" );
document.write( "180-A = 180-180+2A-36<BR>\n" );
document.write( "180-A = 2A-36 Add A to both sides.<BR>\n" );
document.write( "180 = 3A-36 Add 36 to both sides.<BR>\n" );
document.write( "216 = 3A Finally, divide both sides by 3.<BR>\n" );
document.write( "72 = A<BR>\n" );
document.write( "The supplement of A is 180-A<BR>\n" );
document.write( "180-72 = 108 degrees. </SPAN>\n" );
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