document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=490146>Question 490146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Seven less than twice a number x is 19. What is the value of 4x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333873 by </B><A HREF=/tutors/aboutme.mpl?userid=Jstrasner><B>Jstrasner(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jstrasner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jstrasner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hey,<BR>\n" );
document.write( "So for this one we need to write what we know in numbers and variables:<BR>\n" );
document.write( "2x - 7 = 19 <BR>\n" );
document.write( "To solve this equation, we need to isolate the x. So first we add 7 to both sides to get rid of it on the left side:<BR>\n" );
document.write( "2x - 7 + 7 = 19 + 7 => 2x = 26<BR>\n" );
document.write( "Now we divide both sides by 2 to get rid of the 2 on the left side:<BR>\n" );
document.write( "2x/2 = 26/2 => x = 13 <BR>\n" );
document.write( "Now we need to solve 4x. Since x = 13, we substitute 13 for x in the equation:<BR>\n" );
document.write( "4 (13) = 52 <BR>\n" );
document.write( "I hope this helps! </SPAN>\n" );
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