document.write( "Question 490046: 3x+y=4-3x
\n" ); document.write( "2y=x+9\r
\n" ); document.write( "\n" ); document.write( "I can figure the problem out all the way until I have the fraction on the side with y. How do I move the fraction to the other side of the equation to solve for y? I know this is simple but for some reason I just can't seem to figure it out.
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Algebra.Com's Answer #333857 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
6 x + 1 y = 4 .............1
\n" ); document.write( "-1 x + 2 y = 9 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -2
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-12 x -2 y = -8
\n" ); document.write( "-1 x 2 y = 9
\n" ); document.write( "Add the two equations
\n" ); document.write( "-13 x = 1
\n" ); document.write( "/ -13
\n" ); document.write( "x =- 1/13
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "6 x + 1 y = 4
\n" ); document.write( "-0.46 + 1 y = 4
\n" ); document.write( " 1 y = 4 + 0.46
\n" ); document.write( " 1 y = 4.46
\n" ); document.write( " y = 40/9
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