document.write( "Question 490050: write an equation of the line that is perpendicular the the line through (9,10) and (3,-2) and passes through the x-intercept of that line \n" ); document.write( "
Algebra.Com's Answer #333855 by mananth(16946)\"\" \"About 
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x1 y1 x2 y2
\n" ); document.write( "9 10 3 -2
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( -2 - 10 )/( 3 - 9 )
\n" ); document.write( "( -12 / -6 )
\n" ); document.write( "m= 2
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\n" ); document.write( "Plug value of the slope and point ( 9 , 10 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "10.00 = 18 + b
\n" ); document.write( "b= 10 - 18
\n" ); document.write( "b= -8
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = 2 x -8 \r
\n" ); document.write( "\n" ); document.write( "slope = 2 \r
\n" ); document.write( "\n" ); document.write( "slope of perpendicular line = -1/2
\n" ); document.write( "x intercept
\n" ); document.write( "y=0
\n" ); document.write( "2x-8=0
\n" ); document.write( "2x=8
\n" ); document.write( "x=4
\n" ); document.write( "(4,0) and slope -1/2\r
\n" ); document.write( "\n" ); document.write( "Plug value of the slope and point ( 4 , 0 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "0 = -2 + b
\n" ); document.write( "b= 0 - -2
\n" ); document.write( "b= 2
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = - 1/2 x + 2 \r
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\n" ); document.write( "m.ananth@hotmail.ca
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