document.write( "Question 489906: x − 2y = 14
\n" ); document.write( "x + 3y = 9
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #333816 by deborabr(181) $\"\"$ $\"About$

You can put this solution on YOUR website!
x − 2y = 14
\n" ); document.write( "x + 3y = 9
\n" ); document.write( "in this case use the sum method to delete x
\n" ); document.write( "x − 2y = 14 --> change the signal here multiplyin by (-1)
\n" ); document.write( "x + 3y = 9
\n" ); document.write( "so:
\n" ); document.write( "-x + 2y = -14
\n" ); document.write( "x + 3y = 9
\n" ); document.write( "_____________
\n" ); document.write( "0x + 5y = -5
\n" ); document.write( "5y=-5
\n" ); document.write( "y=-5/5
\n" ); document.write( "y=-1
\n" ); document.write( "now substitute y in one of the equations and find x
\n" ); document.write( "taking this x + 3y = 9 get:
\n" ); document.write( "x + 3y = 9
\n" ); document.write( "x + 3*(-1) = 9
\n" ); document.write( "x - 3 = 9
\n" ); document.write( "x = 9+3
\n" ); document.write( "x = 12
\n" ); document.write( "Answer: x=12 and y=-1 \n" ); document.write( "

\n" );