document.write( "Question 489811: Solve in standard form (a + bi) \r
\n" ); document.write( "\n" ); document.write( "(2+i)/i \r
\n" ); document.write( "\n" ); document.write( "I first multiplied by i/i to get the following:\r
\n" ); document.write( "\n" ); document.write( "2i + i^2\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "2i - 1\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "-1 + 2i which is standard form so I thought I was correct.\r
\n" ); document.write( "\n" ); document.write( "However, the student solution manual that I have shows to multiply by -i/-i instead of i/i which is what I did. When doing so they get opposite answer that I do of 1 - 2i. I'm wondering why that manual suggests the answer is 1 - 2i and why they used the negative i over i versus positive. \r
\n" ); document.write( "\n" ); document.write( "I really just need to know or understand how they arrived at using the negative.
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Algebra.Com's Answer #333781 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "It is perfectly OK to use \"i%2Fi\".  You will get the same answer\r\n" );
document.write( "if you do it correctly.  You just made a mistake.\r\n" );
document.write( "\r\n" );
document.write( "The reason they tell you to use \"%28-i%29%2F%28-i%29\" is because they\r\n" );
document.write( "want ONE rule to work for all problems.\r\n" );
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document.write( "When you have \r\n" );
document.write( "\r\n" );
document.write( "\"%28A%2BBi%29%2F%28C%2BDi%29\"\r\n" );
document.write( "\r\n" );
document.write( "They always tell you to multiply by the conjugate of the denominator\r\n" );
document.write( "over itself:\r\n" );
document.write( "\r\n" );
document.write( "\"%28C-Di%29%2F%28C-Di%29\"\r\n" );
document.write( "\r\n" );
document.write( "You problem \"%282%2Bi%29%2Fi\" is really the same as \"%282%2Bi%29%2F%280%2Bi%29\",\r\n" );
document.write( "so to follow that rule you would multiply by \"%280-i%29%2F%280-i%29\",\r\n" );
document.write( "which is the same as \"%28-i%29%2F%28-i%29\".\r\n" );
document.write( "\r\n" );
document.write( "It would also work to use \"%28-C%2BDi%29%2F%28-C%2BDi%29\" but they don't\r\n" );
document.write( "want to tell you to multiply by the negative of the conjugate of\r\n" );
document.write( "the denominator over itself.\r\n" );
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document.write( "Using \"i%2Fi\"\r\n" );
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document.write( "\"expr%28%282%2Bi%29%2Fi%29%2Aexpr%28i%2Fi%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28%282%2Bi%29i%29%2F%28i%2Ai%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%282i%2Bi%5E2%29%2F%28i%5E2%29\"\r\n" );
document.write( "\r\n" );
document.write( "Since \"i%5E2=-1\",\r\n" );
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document.write( "\"%282i%2B%28-1%29%29%2F%28-1%29\"\r\n" );
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document.write( "Separate into two fractions: \r\n" );
document.write( "\r\n" );
document.write( "\"%282i%29%2F%28-1%29+%2B+%28-1%29%2F%28-1%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"-2i+%2B+1\"\r\n" );
document.write( "\r\n" );
document.write( "\"1+-+2i\"\r\n" );
document.write( "\r\n" );
document.write( "----------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Or you can use \"%28-i%29%2F%28-i%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"expr%28%282%2Bi%29%2Fi%29%2Aexpr%28%28-i%29%2F%28-i%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28%282%2Bi%29%28-i%29%29%2F%28%28i%29%28-i%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28-2i-i%5E2%29%2F%28-i%5E2%29\"\r\n" );
document.write( "\r\n" );
document.write( "Since \"i%5E2=-1\",\r\n" );
document.write( "\r\n" );
document.write( "\"%28-2i-%28-1%29%29%2F%28-%28-1%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28-2i%2B1%29%2F1\"\r\n" );
document.write( "\r\n" );
document.write( "\"-2i%2B1\"\r\n" );
document.write( "\r\n" );
document.write( "\"1-2i\"\r\n" );
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document.write( "\r\n" );
document.write( "------------------------\r\n" );
document.write( "\r\n" );
document.write( "Edwin
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