document.write( "Question 489811: Solve in standard form (a + bi) \r
\n" ); document.write( "\n" ); document.write( "(2+i)/i \r
\n" ); document.write( "\n" ); document.write( "I first multiplied by i/i to get the following:\r
\n" ); document.write( "\n" ); document.write( "2i + i^2\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "2i - 1\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "-1 + 2i which is standard form so I thought I was correct.\r
\n" ); document.write( "\n" ); document.write( "However, the student solution manual that I have shows to multiply by -i/-i instead of i/i which is what I did. When doing so they get opposite answer that I do of 1 - 2i. I'm wondering why that manual suggests the answer is 1 - 2i and why they used the negative i over i versus positive. \r
\n" ); document.write( "\n" ); document.write( "I really just need to know or understand how they arrived at using the negative.
\n" ); document.write( "

Algebra.Com's Answer #333780 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"%282%2Bi%29%2Fi\" \r
\n" ); document.write( "\n" ); document.write( "=\"%282%2Bi%29%28-i%29%2Fi%28-i%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28-2i-i%5E2%29%2F%28-i%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28-2i-%28-1%29%29%2F%28-%28-1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28-2i%2B1%29%2F1\"\r
\n" ); document.write( "\n" ); document.write( "=\"-2i%2B1\"\r
\n" ); document.write( "\n" ); document.write( "or \"1-2i\"
\n" ); document.write( "
\n" );