document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489801>Question 489801</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water must be evaporated from 32oz of a 4% solution to make a 6% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333777 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As usual, ans = x = H2O to go into thick air.<BR>\n" );
document.write( "Salt is same quant before and after: 0.06 * (32 -x) = 0.04 * 32<BR>\n" );
document.write( "*100, subtract righhand side:<BR>\n" );
document.write( "6*32 -6x = 4*32<BR>\n" );
document.write( "6x = (6-4)*32<BR>\n" );
document.write( "x = 32/3<BR>\n" );
document.write( "Taking away a third is exactly what you would expect: The remaining thirds have to split the extra 4% salt 2 ways, 4 + 4/2 = 6. </SPAN>\n" );
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