document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489687>Question 489687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leaves at noon with constant velocity of 40 mi/hr another train leaves at 2pm with constant velocity of 70 mi/hr at what mile do they catch up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333733 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a train leaves at noon with constant velocity of 40 mi/hr another train leaves at 2pm with constant velocity of 70 mi/hr at what mile do they catch up?<BR>\n" );
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document.write( "Apply the distance formula of d=rt<BR>\n" );
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document.write( "Let x = time (hours) to catch up<BR>\n" );
document.write( "then<BR>\n" );
document.write( "40(x+2) = 70x<BR>\n" );
document.write( "40x+80 = 70x<BR>\n" );
document.write( "80 = 30x<BR>\n" );
document.write( "80/30 = x<BR>\n" );
document.write( "2.67 hours = x<BR>\n" );
document.write( "or<BR>\n" );
document.write( "2 hours and 40 minutes = x<BR>\n" );
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document.write( "2 pm + 2 hours and 40 minutes = 4:40 pm </SPAN>\n" );
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