document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489684>Question 489684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On the first part of a 317 mile trip, a salesperson averaged 58mph. He averaged only 52mph hour on the last part of the trip because of an increaced volume of traffic. The total time of the trip was 5 hours and 45 minutes. Find the amount of time at each of the two speeds.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333731 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First part = x miles<BR>\n" );
document.write( "second part =317-x  miles\r<BR>\n" );
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document.write( "x/58 + (317-x)/52 = 5 3/4 \r<BR>\n" );
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document.write( "52x+58(317-x)= (23/4) * 52*58\r<BR>\n" );
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document.write( "52x+18386 -58x=17342<BR>\n" );
document.write( "-6x=-1044<BR>\n" );
document.write( "x=174 miles -------- first part\r<BR>\n" );
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document.write( "174/58 = time first part = 3 hours  </SPAN>\n" );
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