document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489619>Question 489619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary if the sum of their measures is 90 degress. If angle A and B are complementary and angle B is 18 degress greater than angle A, find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333714 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary if the sum of their measures is 90 degress. If angle A and B are complementary and angle B is 18 degress greater than angle A, find the measure of each angle.<BR>\n" );
document.write( "Let x = measure of angle A<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x+18 = measure of angle B<BR>\n" );
document.write( ".<BR>\n" );
document.write( "x + (x+18) = 90<BR>\n" );
document.write( "2x+18 = 90<BR>\n" );
document.write( "2x = 72<BR>\n" );
document.write( "x = 36 degrees (angle A)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Angle B:<BR>\n" );
document.write( "x+18 = 36+18 = 54 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );