document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489102>Question 489102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: if log x + log y =2, find xy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333698 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if log x + log y =2, find xy<BR>\n" );
document.write( "log(xy)=2<BR>\n" );
document.write( "in exponential form: base(10) raised to log of number(2)=number(xy)<BR>\n" );
document.write( "10^2=xy=100 </SPAN>\n" );
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