document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=488789>Question 488789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> would someone be able to explain how to solve to find x:\r<BR>\n" );
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document.write( "2 × (0.1)^x+1 = 25\r<BR>\n" );
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document.write( "it would be much appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333693 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 × (0.1)^x+1 = 25<BR>\n" );
document.write( "2 × (0.1)^x = 24<BR>\n" );
document.write( " (0.1)^x = 12<BR>\n" );
document.write( "take log of both sides<BR>\n" );
document.write( "xlog 0.1=log 12<BR>\n" );
document.write( "x=log 12/log 0.1<BR>\n" );
document.write( "x=-1.0792 </SPAN>\n" );
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