document.write( "Question 489516: Hank can row a boat 1 mi upstream against the current in 24 minutes. He can row the same distance downstream in 13 min. If the rowing speed and the current speed are constant, what is Hank's rowing speed, and what is the speed of the current?\r
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Algebra.Com's Answer #333681 by mananth(16946)\"\" \"About 
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boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current x-y 0.40 hours
\n" ); document.write( "with current x+y 0.22 hours
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\n" ); document.write( "Distance = same= 1 miles
\n" ); document.write( "t=d/r
\n" ); document.write( "1 / ( x - y )= 0.40
\n" ); document.write( "0.4 ( x - y ) = 1.00
\n" ); document.write( "0.4 x -0.4 y = 1 ....................1
\n" ); document.write( "1 / ( x + y )= 0.22
\n" ); document.write( "0.22 ( x + y ) = 1
\n" ); document.write( "0.22 x + 0.22 y = 1 ...............2
\n" ); document.write( "Multiply (1) by 0.22
\n" ); document.write( "Multiply (2) by 0.40
\n" ); document.write( "we get
\n" ); document.write( "0.09 x + -0.09 y = 0.22
\n" ); document.write( "0.09 x + 0.09 y = 0.4
\n" ); document.write( "0.17 x = 0.62
\n" ); document.write( "/ 0.17
\n" ); document.write( "x = 3.55 mph
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "0.4 x -0.4 y = 1
\n" ); document.write( "1.42 -0.4 y = 1
\n" ); document.write( "-0.4 y = 1 -1.42
\n" ); document.write( "-0.4 y = -0.42
\n" ); document.write( " y = 1.05 mph
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