document.write( "Question 489288: Vanessa can do a job in 12 days. After she has worked for 4 days, she is joined by Susan, and they finish the job together in 2 more days. How long would it have taken Susan to do the whole job herself? \n" ); document.write( "

Algebra.Com's Answer #333668 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Vanessa can do a job in 12 days. After she has worked for 4 days, she is joined by Susan, and they finish the job together in 2 more days.
\n" ); document.write( " How long would it have taken Susan to do the whole job herself?
\n" ); document.write( ":
\n" ); document.write( "Let s = time required by Susan completing the job by herself
\n" ); document.write( "let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "From the given information we can see that V worked a total of 6 days, S worked 2 days
\n" ); document.write( ":
\n" ); document.write( " $\"6%2F12\"$ + $\"2%2Fs\"$ = 1
\n" ); document.write( "multiply by 12s, results:
\n" ); document.write( "6s + 12(2) = 12s
\n" ); document.write( "24 = 12s - 6s
\n" ); document.write( "24 = 6s
\n" ); document.write( "s = 24/6
\n" ); document.write( "s = 4 days for Susan to do the job alone. \n" ); document.write( "

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