document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=489175>Question 489175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have three problems I can't figure out they are linear equations by addition, they are -3x-5y=-7 eqation 1<BR>\n" );
document.write( "         -4x+5y=14 equation 2\r<BR>\n" );
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document.write( "3x+y=30 equation 1<BR>\n" );
document.write( "-3x+7y=6 equation 2\r<BR>\n" );
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document.write( "2x-y=2<BR>\n" );
document.write( "2x+3y=22\r<BR>\n" );
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document.write( "these are homework quesstion and I am not good at linear equations\r<BR>\n" );
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document.write( "Thank you so much </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333580 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333580\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm guessing your task is to see which pairs of linear relationships reduce to a simple linear equation by the simple process of adding the pair together.<BR>\n" );
document.write( "So just add them term by term, i.e., the x's, the y's, and the right hand side constants.<BR>\n" );
document.write( "In the first pair, (-5y) + (+5y) --> 0 so the result is a linear equation in x.<BR>\n" );
document.write( "Similar in 2nd pair (x terms cancel, y remains).<BR>\n" );
document.write( "Last pair are not helped by addition of equations (substration would do it).<BR>\n" );
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