document.write( "Question 489142: please help me, i have submitted this question several times.
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document.write( "susan forman has to purchase a box of cereal, a bottle dof soda, and a can of vegetables. the types of cereal, soda, and vegetable she is considering are below.
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document.write( "cereal: rice krispies, frosted flakes, honeycomb
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document.write( "soda:orange,black cherry, ginger ale.
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document.write( "vegetables: peas, carrots.\r
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document.write( "a)determine the number of points in the sample space.
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document.write( "b)construct a tree diagram and determine the sample space. determine the probability that she selects:
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document.write( "c) honeycomb for the cerel.
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document.write( "d)rice krispies and ginger ale.
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document.write( "e)a soda other than black cherry. \n" );
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Algebra.Com's Answer #333576 by chessace(471)![]() ![]() You can put this solution on YOUR website! The first step is to count the options in each category: \n" ); document.write( "C: 3 \n" ); document.write( "S: 3 \n" ); document.write( "V: 2 \n" ); document.write( "a) Points in sample space = product of these 3 independent choice counts: 3*3*2 = 18. \n" ); document.write( "b) From root of tree, 3 branches based on and labeled with a choice C. \n" ); document.write( "Each of those 3 branches have 3 more, labeled with choice of S. \n" ); document.write( "Each of those 9 branches have 2 more, labeled with choice of V. \n" ); document.write( "Each of these 18 (see \"a\") terminal nodes are labeled with the 3 selections that were made along the path from root. \n" ); document.write( "The total tree has 3 + 3*3 + 18 = 30 branches. \n" ); document.write( "[that's what I would do, maybe you are supposed to do it differently]. \n" ); document.write( "Now the probabilies aren't known, so assume they are equal within categories. \n" ); document.write( "c) 1/3 \n" ); document.write( "d) (1/3)*(1/3) = 1/9 \n" ); document.write( "e) ((3-1)/3) = 2/3 \n" ); document.write( " \n" ); document.write( " |