document.write( "Question 488937: How do I begin to solve this equation (absolute value bar)2x+1/3x+4(absolute value bar) = 1 \n" ); document.write( "
Algebra.Com's Answer #333493 by stanbon(75887)\"\" \"About 
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How do I begin to solve this equation (absolute value bar)2x+1/3x+4(absolute value bar) = 1
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\n" ); document.write( "|(2x+1)/(3x+4)| = 1
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\n" ); document.write( "Draw a number line.
\n" ); document.write( "Plot x = -1/2 and x = -4//3 on the line
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\n" ); document.write( "Determine the sign of the fraction in each of the three line intervals.
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\n" ); document.write( "If x < -4/3 the fraction is -/- = positive
\n" ); document.write( "So (2x+1)/(3x+4) = 1
\n" ); document.write( "2x+1 = 3x+4
\n" ); document.write( "x = -3
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\n" ); document.write( "If -4/3 < x < -1/2, the fraction is -/+ = negative
\n" ); document.write( "So (2x+1)/(3x+4) = -1
\n" ); document.write( "2x+1 = -3x-4
\n" ); document.write( "5x = -5
\n" ); document.write( "x = -1
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\n" ); document.write( "If x > -1/2 the fraction is +/+ = positive
\n" ); document.write( "You get x = -3 as you did above.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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