document.write( "Question 488896: what is the interest if the Principal is $720, the Rate is 5 1/4% and the Time is 3 years? \n" ); document.write( "
Algebra.Com's Answer #333472 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if the interest is compounded monthly (normal bank practice), then $720.00 would be equal to $847.2093772in 3 years.\r \n" ); document.write( "\n" ); document.write( "if the interest is compounded annually, then $720.00 would be equal to $844.1213401 in 3 years.\r \n" ); document.write( "\n" ); document.write( "if the interest was compounded daily, then $720.00 would be equal to $847.4908701 in 3 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the interest was compounded continuously, then $720.00 would be equal to $847.50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "continuous compounding is given by the formula:\r \n" ); document.write( "\n" ); document.write( "F = P * e^(i*y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "annual, monthly, daily compounding is given by the formula:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F = P * (1+(i/c)^(y*c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P is the present amount \n" ); document.write( "F is the future amount \n" ); document.write( "i is the annual interest rate \n" ); document.write( "y is the number of year \n" ); document.write( "c is the compounding period. \n" ); document.write( "e is the scientific constant of 2.718281828\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for monthly compounding, the variables become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = $725.00 \n" ); document.write( "F = F \n" ); document.write( "i = .0525 \n" ); document.write( "y = 3 \n" ); document.write( "c = 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula of F = P * (1+(i/c))^(y*c) becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F = $724.00 * (1 + (.0525/12))^(*3*12) which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F = $724.00 * (1.004375)^36 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F = $847.2093772 \n" ); document.write( " \n" ); document.write( " |