document.write( "Question 488850: The sum of two numbers is 47. Twice the larger increased by three times the smaller gives a sum of 106. Find each number. \n" ); document.write( "
Algebra.Com's Answer #333465 by lwsshak3(11628)\"\" \"About 
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The sum of two numbers is 47. Twice the larger increased by three times the smaller gives a sum of 106. Find each number.
\n" ); document.write( "**
\n" ); document.write( "let x=larger number
\n" ); document.write( "let y=smaller number
\n" ); document.write( "..
\n" ); document.write( "x+y=47
\n" ); document.write( "x=47-y
\n" ); document.write( "..
\n" ); document.write( "2x+3y=106
\n" ); document.write( "2(47-y)+3y=106
\n" ); document.write( "94-2y+3y=106
\n" ); document.write( "y=106-94=12
\n" ); document.write( "x=47-12=35
\n" ); document.write( "ans:
\n" ); document.write( "The larger number=35
\n" ); document.write( "The smaller number=12 \n" ); document.write( "
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