document.write( "Question 488673: A long distance trucker traveled 180 miles in one direction during a snow storm. The return trip in rainy weather was accompolished at double spped and took 3 hours less time. Find the speed going?\r
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Algebra.Com's Answer #333432 by stanbon(75887)\"\" \"About 
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A long distance trucker traveled 180 miles in one direction
\n" ); document.write( "during a snow storm.
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\n" ); document.write( "The return trip in rainy weather was accomplished at double speed and took 3 hours less time. Find the speed going?
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\n" ); document.write( "Going DATA:
\n" ); document.write( "distance = 120 miles ; rate = x mph ; time = d/r = 180/x hrs\r
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\n" ); document.write( "Return DATA:
\n" ); document.write( "distance = 120 miles ; rate = 2x mph ; time = 120/(2x) = 60/x hrs\r
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\n" ); document.write( "Equation:
\n" ); document.write( "time - time = 3 hrs
\n" ); document.write( "180/x - 60/x = 3 hrs
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\n" ); document.write( "180 - 60 = 3x
\n" ); document.write( "3x = 120
\n" ); document.write( "x = 40 mph (the \"Going\" rate)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "\n" ); document.write( "The speed going was ____mph
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