document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=488289>Question 488289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove the sum of two rational numbers is rational, using real analysis </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333389 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Real analysis would assert that the rational numbers form an ordered field, and that the axiom of closure is satisfied (e.g. the sum of two rational numbers is another rational number in the set).\r<BR>\n" );
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document.write( "It is also very easy to prove this without any sort of analysis. Just let a/b and c/d be your two rational numbers, and <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{a}{b} + \frac{c}{d} = \frac{ad+bc}{bd}\">, also a rational number. </SPAN>\n" );
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