document.write( "Question 50191: Jo as 37 coins(all nickles, dimes, and quarters) worth $5.50. She has 4 more quaters than nickles. How many dimes does Jo have? \n" ); document.write( "
Algebra.Com's Answer #33337 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jo as 37 coins(all nickles, dimes, and quarters) worth $5.50. She has 4 more quaters than nickles. How many dimes does Jo have? \n" ); document.write( "-------------- \n" ); document.write( "Let number of nickels be \"x\" \n" ); document.write( "Value of those nickels is 5x cents. \n" ); document.write( "Number of quarter is \"x+4\" \n" ); document.write( "Value of those quarters is 25(x+4)= 25x+100 cents \n" ); document.write( "Number of dimes = 37-(x+x+4)=33-2x \n" ); document.write( "Value of those dimes = 10(33-2x)=330-20x cents \n" ); document.write( "EQUATION: \n" ); document.write( "value + value + value = 550 cents \n" ); document.write( "5x+25x+100+330-20x=550 \n" ); document.write( "10x=110 \n" ); document.write( "x=11 (number of nickels) \n" ); document.write( "33-2x=33-22=11 (number of dimes) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |