document.write( "Question 47918: 4. The probability that a married man watches a certain television shows is 0.4 and the probability that a married woman watches the show is 0.5, the probability that a man watches the show given that his wife does is 0.7. Find the probability that
\n" ); document.write( "a.) A married couple watches the show and
\n" ); document.write( "b.) At least 1 person of a married couple will watch the show.
\n" ); document.write( "13. A call center operator working in the night shift reports that the average numbers of incoming queries is 3.2 per minute. Determine the probability that during a given minute, there will be
\n" ); document.write( "a.) At most 3 incoming calls?
\n" ); document.write( "b.) Four or more incoming calls?
\n" ); document.write( "14. A company pays its employees an average wage of 60 pesos an hour with a standard deviation of 10 pesos. If the wages are approximately normally distributed and paid to the nearest cent.
\n" ); document.write( "a.) What percentage of the workers receive wages between 48 pesos and 69 pesos an hour inclusive?
\n" ); document.write( "b.) The highest 5% of the employee hourly wages is greater than what amount?
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Algebra.Com's Answer #33334 by stanbon(75887)\"\" \"About 
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4. The probability that a married man watches a certain television shows is 0.4 [P(m)=0.4]and the probability that a married woman watches the show is 0.5 [P(w)=0.5], the probability that a man watches the show given that his wife does is 0.7 [P(m|w)=0.7].
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\n" ); document.write( "Find the probability that
\n" ); document.write( "a.) A married couple watches the show:
\n" ); document.write( "P(m|w)=[P(m and w)]/[P(w)]
\n" ); document.write( "Therefore P(m and w) = 0.7*0.5=0.35
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\n" ); document.write( "\n" ); document.write( "b.) At least 1 person of a married couple will watch the show.
\n" ); document.write( "P(at least 1 person of a couple will watch)= 1- P (neither watch)
\n" ); document.write( "=1 - P(man doesn't watch)*P(woman doesn't watch)
\n" ); document.write( "=1 - 0.6*0.5 = 1- 0.30 = 0.70
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\n" ); document.write( "\n" ); document.write( "13. A call center operator working in the night shift reports that the average numbers of incoming queries is 3.2 per minute. Determine the probability that during a given minute, there will be
\n" ); document.write( "a.) At most 3 incoming calls?
\n" ); document.write( "b.) Four or more incoming calls?
\n" ); document.write( "Can't do these unless you know the standard deviation of number of calls.
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\n" ); document.write( "14. A company pays its employees an average wage of 60 pesos an hour with a standard deviation of 10 pesos. If the wages are approximately normally distributed and paid to the nearest cent.
\n" ); document.write( "a.) What percentage of the workers receive wages between 48 pesos and 69 pesos an hour inclusive?
\n" ); document.write( "Convert 48 and 69 to z scores.
\n" ); document.write( "Find the area under the normal curve above the
\n" ); document.write( "z-interval you find.
\n" ); document.write( "Answer: 70%
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\n" ); document.write( "b.) The highest 5% of the employee hourly wages is greater than what amount?
\n" ); document.write( "Find the z-value corresponding to 95% under the curve. Ans: z=1.645
\n" ); document.write( "Find the corresponding raw score value using mean=60 and std = 10.
\n" ); document.write( "Ans: 76.45
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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