document.write( "Question 488257: 5. Solve using the elimination method. Show your work. If the system has no solution or an infinite number of solutions, state this.
\n" ); document.write( "5x + 5y = 50\r
\n" ); document.write( "\n" ); document.write( "10x + 6y = 84 \r
\n" ); document.write( "\n" ); document.write( "thanks for any help. \n" ); document.write( "
Algebra.Com's Answer #333329 by deborabr(181)\"\" \"About 
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5x + 5y = 50
\n" ); document.write( "10x + 6y = 84
\n" ); document.write( "in the elimination method we delete one of the unknown x or y
\n" ); document.write( "is easiest to delete the x in this case
\n" ); document.write( "look!
\n" ); document.write( "5x + 5y = 50 --> multiply by (-2) to delete x
\n" ); document.write( "10x + 6y = 84 \r
\n" ); document.write( "\n" ); document.write( "-10x-10y=-100 --> sum
\n" ); document.write( "10x+6y=84
\n" ); document.write( "_____________
\n" ); document.write( "-4y=-16 --> change the signal is the same that multiply by (-1) because y is negative
\n" ); document.write( "so:
\n" ); document.write( "4y=16
\n" ); document.write( "y=16/4
\n" ); document.write( "y=4\r
\n" ); document.write( "\n" ); document.write( "substituting to find x:
\n" ); document.write( "5x+5y=50
\n" ); document.write( "5x+5*4=50
\n" ); document.write( "5x+20=50
\n" ); document.write( "5x=50-20
\n" ); document.write( "5x=30
\n" ); document.write( "x=30/5
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "answer: y=4 and x=6
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