document.write( "Question 487961: 9/10(3+8x)+3 greater than or equal to 15 [[9/10 is a fraction by the way)\r
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document.write( "Can you help me solve this please? \n" );
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Algebra.Com's Answer #333302 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 9/10(3+8x)+3 greater than or equal to 15 [[9/10 is a fraction by the way) \n" ); document.write( "** \n" ); document.write( "(9/10)(3+8x)+3≥15 \n" ); document.write( "9(3+8x)/10-12≥0 \n" ); document.write( "LCD:10 \n" ); document.write( "27+72x-120≥0 \n" ); document.write( "72x-93≥0 \n" ); document.write( "72x-93≥0 \n" ); document.write( "x=93/72 \n" ); document.write( "number line: \n" ); document.write( "<.....-....93/72.....+.......> \n" ); document.write( "solution: [93/72,∞) \n" ); document.write( " |