document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50144>Question 50144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help! I'm stuck on this problem that looks pretty simple but I can't can't figure out the answer:\r<BR>\n" );
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document.write( "There were 13 more nickels than dimes and the total value of the coins was $1.85. Find the number of nickels and the number of dimes.\r<BR>\n" );
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document.write( "I know this problem has to do with solving a system with two equations but I can't find the correct two equations.\r<BR>\n" );
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document.write( "Thanks a bunch<BR>\n" );
document.write( "-Molly </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33328 by </B><A HREF=/tutors/aboutme.mpl?userid=lkwtcnj><B>lkwtcnj(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lkwtcnj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since there's more nickels, let the number of dimes be n and the number of nickels is then n + 13. Then the equation becomes:\r<BR>\n" );
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document.write( "(0.05 * (n + 13)) + (0.10 * n) = 1.85\r<BR>\n" );
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document.write( "Just reduce the equation to get n:<BR>\n" );
document.write( "0.05n + 0.65 + 0.10n = 1.85<BR>\n" );
document.write( "0.15n = 1.2<BR>\n" );
document.write( "n = 8\r<BR>\n" );
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document.write( "Then there are 8 dimes and 21 nickels. Hope that helps! </SPAN>\n" );
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