document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=488076>Question 488076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The terminal side of an angle theta in standard position coincides with the line 3x+y=0 in Quadrant II. Find csc theta to the nearest thousandth.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333253 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The terminal side of an angle theta in standard position coincides with the line 3x+y=0 in Quadrant II. Find csc theta to the nearest thousandth.<BR>\n" );
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document.write( "y = -3x<BR>\n" );
document.write( "When x = -1, y = 3<BR>\n" );
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document.write( "Then r = sqrt(x^2+y^2) = sqrt(1+9) = sqrt(10)<BR>\n" );
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document.write( "csc(theta) = r/y = 1/3)sqrt(10) = 1.054\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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