document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487925>Question 487925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> marin caswell needs 10% hydrochloric acid for a chemistry experiment. how much 5% acid should she mix with 60mL of 20% acid to get a 10% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333207 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As usual answer = x = mL of 5% acid to be added to 60 mL of 20%.<BR>\n" );
document.write( "Focus on acid content:<BR>\n" );
document.write( "Old + Added = New<BR>\n" );
document.write( "60 * .2 + x * 0.05 = (60 + x) * 0.1<BR>\n" );
document.write( "12 + 0.05 x = 6 + 0.1 x<BR>\n" );
document.write( "x (0.1 - 0.05) = 12 - 6<BR>\n" );
document.write( "0.05 x = 6<BR>\n" );
document.write( "x = 120 mL<BR>\n" );
document.write( "Which is what one would hope for: that on a see-saw supported at 10, you need 2 units at 5 to balance 1 at 20.\r<BR>\n" );
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