document.write( "Question 487869: Jack travels from A to B at 30 mph, and returns at 10 mph. Jill leaves at the same time as Jack, and travels from A to B and back at a constant speed of 20 mph. Who gets back first? \n" ); document.write( "
Algebra.Com's Answer #333176 by ankor@dixie-net.com(22740)\"\" \"About 
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Jack travels from A to B at 30 mph, and returns at 10 mph.
\n" ); document.write( "Jill leaves at the same time as Jack, and travels from A to B and back at a constant speed of 20 mph.
\n" ); document.write( " Who gets back first?
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\n" ); document.write( "let d = the one way distance
\n" ); document.write( "let a = Jack's average speed for the round trip
\n" ); document.write( ":
\n" ); document.write( "write a time equation
\n" ); document.write( "\"d%2F30\" + \"d%2F10\" = \"%282d%29%2Fa\"
\n" ); document.write( "Multiply by 30a
\n" ); document.write( "da + 3da = 30(2d)
\n" ); document.write( "da + 3da = 60d
\n" ); document.write( "Simplify divide by d
\n" ); document.write( "a + 3a = 60
\n" ); document.write( "4a = 60
\n" ); document.write( "a = \"60%2F4\"
\n" ); document.write( "a = 15 mph av speed, obviously, Jill will get back first
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