document.write( "Question 487869: Jack travels from A to B at 30 mph, and returns at 10 mph. Jill leaves at the same time as Jack, and travels from A to B and back at a constant speed of 20 mph. Who gets back first? \n" ); document.write( "
Algebra.Com's Answer #333176 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jack travels from A to B at 30 mph, and returns at 10 mph. \n" ); document.write( "Jill leaves at the same time as Jack, and travels from A to B and back at a constant speed of 20 mph. \n" ); document.write( " Who gets back first? \n" ); document.write( ": \n" ); document.write( "let d = the one way distance \n" ); document.write( "let a = Jack's average speed for the round trip \n" ); document.write( ": \n" ); document.write( "write a time equation \n" ); document.write( " \n" ); document.write( "Multiply by 30a \n" ); document.write( "da + 3da = 30(2d) \n" ); document.write( "da + 3da = 60d \n" ); document.write( "Simplify divide by d \n" ); document.write( "a + 3a = 60 \n" ); document.write( "4a = 60 \n" ); document.write( "a = \n" ); document.write( "a = 15 mph av speed, obviously, Jill will get back first \n" ); document.write( " \n" ); document.write( " |