document.write( "Question 487728: 24.
\n" ); document.write( "a = 1 + b,\r
\n" ); document.write( "\n" ); document.write( "b = 5 − 2a\r
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\n" ); document.write( "\n" ); document.write( "Thanks for any help.
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Algebra.Com's Answer #333172 by ankor@dixie-net.com(22740)\"\" \"About 
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a = 1 + b,
\n" ); document.write( "b = 5 − 2a
\n" ); document.write( "Using the 1st equation, we can replace a with (1+b) in the 2nd equation
\n" ); document.write( "b = 5 - 2(1+b)
\n" ); document.write( "b = 5 - 2 - 2b
\n" ); document.write( "b + 2b = 5 - 2
\n" ); document.write( "3b = 3
\n" ); document.write( " b = 1
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\n" ); document.write( "Find a using the 1st equation, replace b with
\n" ); document.write( "a = 1 + 1
\n" ); document.write( "a = 2
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\n" ); document.write( "Check these solutions in the 2nd equation b = 5 - 2a
\n" ); document.write( "1 = 5 - 2(2)
\n" ); document.write( "1 = 5 - 4
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