document.write( "Question 487728: 24.
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document.write( "a = 1 + b,\r
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document.write( "b = 5 − 2a\r
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document.write( "Thanks for any help. \n" );
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Algebra.Com's Answer #333172 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a = 1 + b, \n" ); document.write( "b = 5 − 2a \n" ); document.write( "Using the 1st equation, we can replace a with (1+b) in the 2nd equation \n" ); document.write( "b = 5 - 2(1+b) \n" ); document.write( "b = 5 - 2 - 2b \n" ); document.write( "b + 2b = 5 - 2 \n" ); document.write( "3b = 3 \n" ); document.write( " b = 1 \n" ); document.write( ": \n" ); document.write( "Find a using the 1st equation, replace b with \n" ); document.write( "a = 1 + 1 \n" ); document.write( "a = 2 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check these solutions in the 2nd equation b = 5 - 2a \n" ); document.write( "1 = 5 - 2(2) \n" ); document.write( "1 = 5 - 4 \n" ); document.write( " |