document.write( "Question 487851: A 37 year old father has a 4 year old son. In how many years will the father be exactly 4 times as old as his son. \n" ); document.write( "
Algebra.Com's Answer #333159 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A 37 year old father has a 4 year old son. \n" ); document.write( " In how many years will the father be exactly 4 times as old as his son. \n" ); document.write( ": \n" ); document.write( "Let y = no. of years until this is true \n" ); document.write( ": \n" ); document.write( "y + 37 = 4(y + 4) \n" ); document.write( "y + 37 = 4y + 16 \n" ); document.write( "37 - 16 = 4y - y \n" ); document.write( "21 = 3y \n" ); document.write( "y = \n" ); document.write( "y = 7 years \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can confirm this: 37 + 7 = 4(7 + 4) \n" ); document.write( " |