document.write( "Question 487841: Find the vertex of -0.2x^2+12x+11
\n" ); document.write( "I have used two different methods and came up with two different answers. I have solved for the x= 30 but when I went to do the maximum value I used two solutions and that is where I came up with different answers. The first I substituted the 30 in to the equation -0.2(30)^2+12(30)+11= 191; on the second I used the formula 4ac-b^2 /4a with a= -0.2 b= 12 c=11 I got 4(-0.2)(11)-12^2 divided by 4(-0.2) and came to the answer 169.
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Algebra.Com's Answer #333152 by nerdybill(7384)\"\" \"About 
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Find the vertex of -0.2x^2+12x+11
\n" ); document.write( "the x-value of the vertex:
\n" ); document.write( "x = -b/(2a)
\n" ); document.write( "x = -12/(2*(-0.2))
\n" ); document.write( "x = -12/(-0.4)
\n" ); document.write( "x = 30
\n" ); document.write( ".
\n" ); document.write( "y-value of vertex:
\n" ); document.write( "-0.2x^2+12x+11
\n" ); document.write( "-0.2(30)^2+12(30)+11
\n" ); document.write( "-0.2(900)+12(30)+11
\n" ); document.write( "191
\n" ); document.write( ".
\n" ); document.write( "vertex is at (30, 191)
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